|
A light-based device for solving the Hamiltonian path problem
Department of Computer Science, Unconventional Computation (UC' 06) LNCS 4135, pp. 217-227, Springer-Verlag, 2006
1 IntroductionUsing the light to perform computations is an exciting idea whose applications can be already seen on the market. An important step was made by Intel researchers who have developed the first continuous wave all-silicon laser using a physical property called the Raman Effect [7, 16, 17, 18]. The device could lead to such practical applications as optical amplifiers, lasers, wavelength converters, and new kinds of lossless optical devices. Another solution comes from Lenslet [13] which has created a very fast processor for vector-matrix multiplications. This processor can perform up to 8000 Giga Multiple-Accumulate instructions per second. Lenslet technology has already been applied to data analysis using k-mean algorithm [15] and video compression. In this paper we suggest a new way of performing computations by using some properties of light waves. The idea may be used within a special device for solving the Hamiltonian path problem. We are not taking into account the quantum properties of light which have been used for solving the Traveling Salesman Problem [4, 10]. The paper is organized as follows: The Hamiltonian path problem is briefly described in section 2. The proposed device is presented in section 3. Mathematical background of the labeling system is described in section 3.2. The way in which the proposed device works is given in section 3.3. A list of components required by the proposed device is given in section 3.4. Complexity is discussed in section 3.5. Suggestions for improving the device are given in sections 3.8 and 3.9. Further work directions are suggested in section 4. 2 The Hamiltonian path problemThe description of the Hamiltonian Path (HP) problem for a direct graph is the following:Given a directed graph G = (V, E) with |V| = n nodes and a start node (vstart) and a stop node (vstop), the problem asks to compute is there is a simple path, beginning with node vstart and ending with node vstop, containing all nodes exactly once. The output for this decision problem is either YES or NO depending on whether the Hamiltonian path does exist or not. The Hamiltonian path problem arises in many real-word applications [3, 6]. The problem belongs to the class of NP-complete problems [9]. No polynomial time algorithm is known for it. A small instance of this problem was also the first problem solved using a DNA computer [1]. 3 The proposed deviceOur idea is based on two properties of light:
This section deeply describes the proposed system. First step is to find a way to mark the signals which passes through nodes such that the interesting signals can be easily identified at the destination node. The mathematical background required for this operation is described in section 3.2 and the hardware implementation of the labeling system is described in section 3.4. 3.1 Labeling systemAt the destination node we will wait for a particular ray which has passed through all nodes of the graph exactly once. This is why we need to find a way to label that particular ray so that it could be easily identified.Actually we are interested in marking all rays which pass through a particular node with a unique label, such that Hamiltonian path is uniquely identified at the destination node (vstop). In the solution proposed in this paper, the rays passing through a node are marked by delaying them with a certain amount of time. This delay can be easily obtained by forcing the rays to pass through an optical fiber of a certain length. Roughly speaking, we will know if a certain ray has traversed a Hamiltonian path only if its delay (at the destination node) is equal to the sum of delays of all nodes in that graph. We will also know the particular moment when the expected ray (the one which has completed a Hamiltonian path) will arrive. In this case the only thing that we have to do is to "listen" if there is a fluctuation in the intensity of the signal at that particular moment. Due to the special properties of the proposed system we know that no other ray will arrive, at the destination node, at the moment when the Hamiltonian path ray has arrived. The delays, which are introduced by each node, cannot take any values. If we would put random values for delays we might have different rays (which are not Hamiltonian paths) arriving, at the destination node, in the same time with a ray representing a Hamiltonian path. We need only the ray, which has traversed a Hamiltonian path, to arrive in the destination node at the moment equal to the sum of delays of each node (the moment when the ray has entered in the start node is considered moment 0). Thus, the delaying system must have the following property: Property of the delaying system Let us denote by d1, d2, ..., dn the delays introduced by each node of the graph. A correct set of values for this system must satisfy the condition: d1+d2+...+dn ≠ a1 * d1+a2 * d2+...+an * dn, where ai (1 ≤ i ≤ n) are natural numbers and cannot be all 1 in the same time. If a given value ai is strictly greater than 1 it means that the ray has passed at least twice through node 1. 3.2 Mathematical background for the labeling systemFinding the appropriate labeling system was two steps process. First of all we have written a computer program which generates this numbers by using a backtracking procedure [5]. We also wanted to generate numbers such that the highest number in a system is the smallest possible. This will ensure that the network is constructed in an efficient way. The labeling systems generated by our computer programs are given in Table 1.From Table 1 it can easily seen these numbers follow a general rule: For a graph with n nodes one of the possible labeling systems is: 2n−2n−1, 2n−2n−2, 2n−2n−3, ... , 2n−20. As the second step we have to prove that the property of delaying system (see section 3.1) holds for this sequence of numbers. Actually we have to prove that the equality:
is not possible unless all ai are equal to 1. The left part of the equality is: 2n−2n−1 + 2n−2n−2 + 2n−2n−3 + ... + 2n−20 = n * 2n − (2n−1 + 2n−2 + 2n−3 + ... + 20) = n * 2n − 2n + 1 = (n − 1) * 2n + 1. First of all we have to see that the equality does not hold if all ai numbers are at least 1 and at least one number is strictly greater than 1. If this happens the 2n term will be represented at least n times. But, it must be represented only n−1 times (see above). Thus, if at least one number ai is strictly greater than 1, it means that other numbers aj must be 0. We will prove that the equality (1) does not hold in this case too. As discussed above, if one of the coefficients is 0, at least one of the other coefficients must be strictly greater than 1. For instance, if a1 is set to 0, it means that a2 must be set to 3 in order to compensate the missing 2n−1 term. This is a direct consequence of the fact that 2n−1 = 2 ⋅ 2n−2. Of course, we also have to take into account that 2n−2 must be represented once. This is why we have to set a2 to value 3. If a2 is also 0 we have to set a3 to value 7 (we need 4 * 2n−3 in order to compensate the missing term 2n−1, we also need 2 * 2n−3 to compensate the missing term 2n−2 and, of course, the term 2n−3 must be represented 1 time). As a general idea: if a particular term (2n−j) is missing (the corresponding coefficient aj is set to 0), it can be compensate by setting one of the next coefficients to a value of at least 3. But, a coefficient set to 0 means that the term 2n is missing once, and by setting another coefficient to at least 3 we will get at least 2 extra representations for 2n. This will mean that right part of the equation (1) will be at least (n+1) * 2n + 1. But, the left part of the equation is only (n−1) * 2n + 1. With this we have shown that all ai (1 ≤ i ≤ n) must be 1 in order to have equality in equation (1). For any other values of ai the equality (1) does not hold. An important question is whether this system is the minimal possible (the biggest number is the minimal possible). A partial answer to this question is given in section 3.5.
3.3 How the system worksAn schematic example of a graph-like system is given in Figure 1.In the graph depicted in Figure 1 the light will enter in node 1. It will be delayed with a certain amount of time and then it will be divided into 2 rays which will be sent to the nodes 3 and 5. In node 3 the ray will be delayed (with the amount of time corresponding to node 3) and then it will be sent to node 4. However, this is not a Hamiltonian path because it has visited only the nodes 1, 3 and 4. The other ray which was sent to node 5 (from node 1) can generate a Hamiltonian path by following the route 1, 5, 2, 3 4. Note that there is also a cycle in the graph: 1, 5, 2. The cycle will make that some particular rays to be trapped within the system. The rays which have passed once through the previously described cycle are not considered Hamiltonian paths because the moments when they arrive at the destination node are greater than the sum of delays introduced by each node. The partial paths traversed by rays are given below: 1 1, 3 1, 3, 4 1, 5 1, 5, 2 1, 5, 2, 1 .............{paths starting with 1, 5, 2, 1} 1, 5, 2, 3 1, 5, 2, 3, 4 1, 5, 2, 4 3.4 Hardware implementation of the labeling systemFor implementing the proposed device we need the following components:
3.5 ComplexityThis section answers a very important question: Why the proposed approach is not a polynomial-time solution for the HP problem?At the first sight one may be tempted to say that the proposed approach provides a solution in polynomial time to any instance of the HP problem. The reason behind such claim is given by the ability of the proposed device to provide output to any instance by traversing only once all nodes (O(n) complexity). This could mean that we have found a polynomial-time algorithm for the HP problem. A direct consequence is obtaining solutions, in polynomial time, for all other NP-Complete problems - since there is a polynomial reduction between them [9]. However, this is not our case. As can be seen from Table 1 the delay time increases exponentially with the number of nodes. Even if the ray has to traverse only n nodes (resulting a complexity of O(n)), the total time required by the ray to reach the destination node increases exponentially with the number of nodes. There are two direct consequences which are derived from here:
3.6 Problem sizeWe are interested in computing the size of the cables required to solve a certain instance of the problem in a small amount of time. This will give as a rough indication on the size of the graphs that can be solved using our system in reasonable time.This size heavily depends on the accuracy of the measurement tools. The rise-time of the best oscilloscope available on the market is in the range of picoseconds (10−12 seconds). This means that we should not have two signals that arrive at 2 consecutive moments at a difference smaller than 10−12 seconds. Knowing that the speed of light is 3 * 108 m/s we can easily compute the minimal cable length that should be traversed by the ray in order to be delayed with 10−12 seconds. This is obviously 0.0003 meters. This value is the minimal delay that should be introduced by a node in order to ensure that the difference between the moments when two consecutive signals arrive at the destination node is greater or equal to the measurable unit of 10−12 seconds. This will also ensure that we will be able to correctly identify whether the signal has arrived in the destination node at a moment equal to the sum of delays introduced by each node. No other signals will arrive within a range of 10−12 seconds around that particular moment. Once we have the length for that minimal delay is quite easy to compute the length of the other cables that are used in order to induce a certain delay. Recall from section 3.2, Table 1 that a graph with 5 nodes has the following delaying system: 16, 24, 28, 30, 31. From the previous reasoning line we have deduced
that the smaller indivisible unit is 0.0003. So, we have to multiply
these numbers by 0.0003. We obtain: These numbers represent the length of the cables that must be used in
graph's nodes in order to induce a certain delay.
2n * 0.0003 = 3 * 108 (2)
This number is about 40 nodes. However, the length of the optic fibers used for inducing the largest delay for this graph is huge: about 8 * 108 meters. We cannot expect to have such long cables for our experiments. However, shorter cables (of several hundreds of kilometers) are already available in the internet networks. They can be easily used for our purpose. Assuming that the longest cable that we have is about 300 kilometers we may solve instances with about 26 nodes. The amount of time required to obtain a solution is about 10−6 seconds. Note that the maximal number of nodes can be increased when the precision of our measurement instruments (oscilloscope and photodiode) is increased. Also note that this difficulty is not specific to our system only. Other major unconventional computation paradigms, trying to solve NP-complete problems share the same fate. For instance, a quantity of DNA equal to the mass of Earth is required to solve HP instances of 200 cities using DNA computers [11]. 3.7 Amplifying the signalBeam splitters are used in our approach for dividing a ray in two or more subrays. Because of that, the intensity of the signal is decreasing. In the worst case we have an exponential decrease of the intensity. For instance, in a graph with n nodes, each signal is divided (within each node) into n − 1 signals. Roughly speaking, the intensity of the signal will decrease nn times.This means that, at the destination node, we have to be able to detect very small fluctuations in the intensity of the signal. For this purpose we will use a photomultiplier [8] which is an extremely sensitive detector of light in the ultraviolet, visible and near infrared range. This detector multiplies the signal produced by incident light by as much as 108, from which even single photons can be detected. 3.8 Improving the device by reducing the speed of the signalThe speed of the light in optic fibers is an important parameter in our device. The problem is that the light is too fast for our measurement tools. We have either to increase the precision of our measurement tools or to decrease the speed of light.It is known that the speed of light traversing a cable is significantly smaller than the speed of light in the void space. Commercially available cables have limit the speed of the ray wave up to 60% from the original speed of light. This means that we can obtain the same delay by using a shorter cable. However, this method for reducing the speed of light is not enough. The order of magnitude is still the same. This is why we have the search for other methods for reducing that speed. A very interesting solution was proposed in [12, 14] which is able to reduce the speed of light by 7 orders of magnitude. This could help our mechanism significantly. However, is still a question how to use this idea for our device because of the complex equipment involved in those experiments [12, 14]. By reducing the speed of light by 7 orders of magnitude we can reduce the size of the involved cables by a similar order. This will help us to solve larger instances of the problem. 3.9 Improving the performance of the device for particular graphsThe labeling system proposed in section 3.1 is a general one. It can be used for any kind of graph (with any number of nodes and arcs). We have shown that this system has a big problem: the value of the involved numbers increase exponentially with the number of nodes in the graph being solved.But, for particular graphs we can find other labeling systems which are not exponential. For example, the linear graph (see Figure 2 can be solved by our device by using virtually no delays. In this case the moment when the signal arrives in the destination node is equal to sum of delays introduced by the cables connecting the nodes. Finding the optimal labeling system for a particular graph is an interesting problem which will be investigated in the near future. 3.10 Technical challengesThere are many technical challenges that must be solved when implementing the proposed device. Some of them are:
4 Conclusions and further workThe way in which light can be used for performing useful computations has been suggested in this paper. The techniques are based on the massive parallelism of the light ray.It has been shown the way in which a light-based device can be used for solving the Hamiltonian path problem. Using the today technology we can build a light-based device which can solve small and medium size instances in several seconds. Further work directions will be focused on:
References
|